carenzaleah41
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G= 10m/s
A 50kg student jumps out of a window onto a pile of mattresses.
(a) Ignoring air resistance, what is her increase in speed each second?

B) What is her change of momentum each second?

Sagot :

mickymike92

The increase in velocity of the student per second is 10 m/s^2 and her change in momentum each second is 500 kgm/s^2.

What is the change in velocity per second for any object falling freely under gravity?

The change in velocity of a moving object is known as acceleration.

For any object falling freely under gravity, the change in velocity per second or acceleration due to gravity is a constant and is equal to 10 metres per square second (10 m/s^2).

The change in momentum of a body is given as follows:

  • Momentum = mass × velocity
  • Change in momentum = mv - mu
  • Change in momentum = m(v - u)
  • acceleration = v - u

where m is mass, v is final velocity and u is final velocity.

Mass of the student = 50 Kg

Change in momentum each second = 50 kg × 10 m/s^2 = 500 kgm/s^2

Therefore, the increase in velocity of the student per second is 10 m/s^2 and her change in momentum each second is 500 kgm/s^2.

Learn more about change in momentum at: https://brainly.com/question/27778439

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