Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
The angular acceleration of a bike with tires of radius 0.330 m speeds up from rest to 5.33 m/s in 6.27 s will be 2. 57 rad/s²
What is angular acceleration?
Angular acceleration can be defined as the time it takes for a change in angular velocity. It is denoted as 'α' with a unit of rads/s²
It is expressed thus;
α= Δω ÷ Δt
Where α = angular acceleration
Δw = change in angular velocity = velocity ÷ radius
Δ t = change in time
How to calculate the angular acceleration
Using the formula:
α= Δω ÷ Δt
v = 5. 33m/s, r = 0. 33m and t = 6.27s
Substitute the values to get the angular velocity
Δw = v÷ r = 5. 33 ÷ 0.330 = 16. 15 m/s
Substitute the value of Δw into the equation
α= Δω ÷ Δt = 16. 15 ÷ 6. 27 = 2. 57 rad/s²
Therefore, the angular acceleration of a bike with tires radius of 0. 330m, speed of 5. 33mls in 6. 27s is 2. 57 rad/s²
Learn more about angular acceleration here:
https://brainly.com/question/21278452
#SPJ1
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
