Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

How much of an 80% orange juice drink must be mixed with 12 gallons of a 20% orange juice drink to obtain a mixture that is 50% orange juice

Sagot :

sqdancefan

Answer:

  12 gallons

Step-by-step explanation:

The amount of juice in the mix is the sum of the amounts of juice contributed by each of the constituents of the mix. Those amounts will be the product of the quantity of constituent and the fraction that is juice.

__

setup

Let x represent the amount of 80% juice drink that must be added to the mix. The total amount of orange juice in the mix is ...

  20% × 12 gallons + 80% × x gallons = 50% × (12 +x) gallons

__

solution

Dividing by gallons, eliminating parentheses, and using decimals for percentages, we have ...

  2.4 +0.80x = 6.0 +0.50x

  0.30x = 3.6 . . . . . . . . subtract 0.50x+2.4

  x = 12 . . . . . . . . . . . divide by 0.30

12 gallons of 80% juice drink must be added to obtain the desired mix.

_____

Additional comment

We notice that 50% is the average of 20% and 80%, so each must be half of the mix. If there are 12 gallons of 20%, then there must be 12 gallons of 80%.

You can read more about mixture problems here:

https://brainly.com/question/26751698

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.