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Sagot :
(a) The initial speed at which the bottles are launched is 4.27 m/s.
(b) The horizontal displacement at which the bottle land is 1.75 m.
Initial speed of the bottle
The initial speed of the bottle is calculated as follows;
[tex]T = \frac{2usin\theta}{g}[/tex]
where;
- T is time of flight
- u is the initial speed
2usinθ = Tg
u = Tg/(2sinθ)
u = (0.5 x 9.8)/(2 x sin35)
u = 4.27 m/s
Horizontal displacement of the bottle
X = u²sin(2θ)/g
X = (4.27² x sin(70))/(9.8)
X = 1.75 m
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