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Sagot :
Since the square root of
x=√x
and the cube root of
x=3√x
and their product
=√x × 3√x
= x1/2 × x1/3 [Since, n√a =a 1/n]
=x1/2+1/3 [Since, a^m ×a^n =a^m+n]
=x^3+2 /6
= x 5/6
Therefore, required product is
=√6x5
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Answer:
[tex]x^2y^3[/tex]
Step-by-step explanation:
[tex]\text{Square of}~ x =x^2\\\\\text{Cube of}~ y = y^3\\\\\text{Product} = x^2y^3[/tex]
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