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If α and β are the zeros of the quadratic polynomial f(x) = 6x²+x-2, then the value of

1. α²+β²
2. 1/α+1/β​

Can Someone Answer This Quick Thank You<3​


Sagot :

Answer:

1. α²+β² = 25/36

2. 1/α+1/β​ = 1/2

Step-by-step explanation:

Formula :

Consider the quadratic equation ax² + bx + c = 0

Where x₁ and x₂ are the zeros of the equation.

Then

[tex]x_{1}+x_{2}=-\frac{b}{a} \\x_{1}\times x_{2}=\frac{c}{a}[/tex]

……………………………………

α and β are the zeros of the quadratic polynomial f(x) = 6x²+x-2

Then

[tex]\alpha +\beta =-\frac{1}{6}[/tex]

[tex]\alpha \times \beta =-\frac{1}{3}[/tex]

……………………

[tex]\alpha^{2} +\beta^{2} =\left( \alpha +\beta \right)^{2} -2\alpha \beta[/tex]

            [tex]=\alpha^{2} +\beta^{2} =\left( -\frac{1}{6} \right)^{2} -2\times(-\frac{1}{3} )[/tex]

            [tex]=\frac{25}{36}[/tex]

………………………………

[tex]\frac{1}{\alpha } +\frac{1}{\beta } =\frac{\alpha +\beta }{\alpha \beta }[/tex]

          [tex]=\frac{-\frac{1}{6} }{-\frac{1}{3} } =\frac{1}{2}[/tex]