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If p+q = - 2, show that p^3 + q^3 +8 =6pq

Sagot :

devishri1977

Answer:

Step-by-step explanation:

Algebraic Identities:

Identity used:  (a +b)³ = a³ + b³ + 3ab(a +b)

       p + q = -2  ------------------(I)

Both sides take cube,

        (p +q)³ = (-2)³          

a = p and b =q

  p³ + q³ + 3pq(p +q) = -8

  p³ + q³ + 3pq*(-2)   = - 8        {From (I)}

  p³ + q³  - 6pq         = -8

                  p³ + q³    = -8 + 6pq

             p³ + q³   + 8 = 6pq

Hence, proved.

     

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