Nathan needs some paint for his bedroom. He finds two cans of white paint, four cans of green paint and three cans of pink paint in his garage. If he chooses a can of paint without looking at the color, what is the chance that he will paint his bedroom pink?

A. 1/3
B. 2/9
C. 2/3
D. 6/9

Question

04-06-2022
Mathematics

Answered

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Nathan needs some paint for his bedroom. He finds two cans of white paint, four cans of green paint and three cans of pink paint in his garage. If he chooses a can of paint without looking at the color, what is the chance that he will paint his bedroom pink?

A. 1/3
B. 2/9
C. 2/3
D. 6/9

Sagot :

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facundo3141592 facundo3141592 · Answer 1 · 2022-06-06T06:28:01-04:00

The probability of randomly selecting a can of pink paint is P = 1/3, so the correct option is A.

What is the chance that he will paint his bedroom pink?

Assuming that all the cans of paint have the same probability of being randomly selected, the probability that he will choose a pink can is equal to the quotient between the number of pink cans and the total number of cans.

There are 2 cans of white, 4 cans of green, and 3 cans of pink, so a total of 9 cans.

Then the probability is:

P = 3/9 = 1/3.

The correct option is A.

If you want to learn more about probability:

https://brainly.com/question/251701

#SPJ1

Nathan needs some paint for his bedroom. He finds two cans of white paint, four cans of green paint and three cans of pink paint in his garage. If he chooses a can of paint without looking at the color, what is the chance that he will paint his bedroom pink? A. 1/3 B. 2/9 C. 2/3 D. 6/9

Sagot :

What is the chance that he will paint his bedroom pink?

Other Questions

Nathan needs some paint for his bedroom. He finds two cans of white paint, four cans of green paint and three cans of pink paint in his garage. If he chooses a can of paint without looking at the color, what is the chance that he will paint his bedroom pink?

A. 1/3
B. 2/9
C. 2/3
D. 6/9