By solving a quadratic equation, we will see that the length is 10m and the width is 6.5m
How to find the length and width of the rectangle?
For a rectangle of width W and length L, the area is:
A = W*L
In this case, we know that the area is 65m² and that the length is 3 meters less than 2 times the width, so:
L = 2*W - 3m
Then we can write:
65m² = (2*W - 3m)*W = 2*W² - 3m*W
This is a quadratic equation:
2*W² - 3m*W - 65m² = 0.
The solutions are given by the Bhaskara's formula:
[tex]W = \frac{3 \pm \sqrt{(-3)^2 - 4*2*(-65)} }{2*2} \\\\W = \frac{3 \pm 23 }{4}[/tex]
We only care for the positive solution, which is:
W = (3m + 23m)/4 = 26m/4 = 6.5m
Then the length is:
L = 2*6.5m - 3m = 10m
If you want to learn more about rectangles:
https://brainly.com/question/24571594
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