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Sagot :
[1] 0.25, 0.25%, or [tex]\frac{1}{4}[/tex]
We will divide the number of wanted outcomes by possible outcomes.
[tex]\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{5}{3+5+12} =\frac{5}{20} =\frac{1}{4}[/tex]
[2]
We will follow the same steps as problem 1.
MTHMTCS = 7 consonants
AEAI = 4 vowels
MTHEMTICS = 9 letters that are not A's
MATHEMATICS = total of 11 letters
(a)
[tex]\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{7}{11}[/tex]
(b)
[tex]\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{4}{11}[/tex]
(c)
[tex]\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{9}{11}[/tex]
[3] 0.877
If the probability that a television is defective is 0.123, then the probability that a television is not defective is:
1 - 0.123 = 0.877
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