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Which of the following is an asymptote of y=csc(x)?
x= -pi
x= -pi/3
x= pi/4
x= pi/2

Sagot :

VectorFundament120

Answer:

x = -π

Step-by-step explanation:

An asymptote line is a line that the graph does not intercept or pass through but rather approaches it. An asymptote line also is considered to be a line of undefined value of function because if an asymptote is x = a then f(a) is undefined.

The question gives a function y = csc(x) which is in another form, y = 1/sin(x).

We have to find the value of x that turns the function in undefined and that x-value will be your asymptote.

From a unit circle, we know that sin(-π) = -sin(π) = 0. Since sin(-π) = 0 —> y = csc(-π) = 1/sin(-π) = 1/0

Now we find out that at x = -π, csc(x) is not defined and hence, an asymptote is x = -π

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