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Line segment AB has endpoints A(1,8) and B(7,−4). What are the coordinates of the point located 5/6 of the way from A to B?
O (-4, 11 1/3)
O (3, -2 1/3)
O (6, -2)
O (12, -14)


Sagot :

The coordinate of the point is (6,-2)

How to determine the coordinate of the point?

The given parameters are:

A = (1,8)

B = (7,-4)

The location of the point (i.e 5/6) means that the ratio is:

m :n = 5 : (6 - 5)

m : n = 5 : 1

The coordinate of the point is then calculated as:

[tex](x,y) = \frac{1}{m + n}* (mx_2 + nx_1,my_2 + ny_1)[/tex]

So, we have:

[tex](x,y) = \frac{1}{5 + 1}* (5 * 7 + 1 * 1 , 5 * -4 + 1 * 8)[/tex]

Evaluate

[tex](x,y) = \frac{1}{6}* (36 , -12)[/tex]

Evaluate the product

(x,y) = (6,-2)

Hence, the coordinate of the point is (6,-2)

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