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Sagot :
The coordinate of the point is (6,-2)
How to determine the coordinate of the point?
The given parameters are:
A = (1,8)
B = (7,-4)
The location of the point (i.e 5/6) means that the ratio is:
m :n = 5 : (6 - 5)
m : n = 5 : 1
The coordinate of the point is then calculated as:
[tex](x,y) = \frac{1}{m + n}* (mx_2 + nx_1,my_2 + ny_1)[/tex]
So, we have:
[tex](x,y) = \frac{1}{5 + 1}* (5 * 7 + 1 * 1 , 5 * -4 + 1 * 8)[/tex]
Evaluate
[tex](x,y) = \frac{1}{6}* (36 , -12)[/tex]
Evaluate the product
(x,y) = (6,-2)
Hence, the coordinate of the point is (6,-2)
Read more abut line segment ratio at:
https://brainly.com/question/12959377
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