Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Evaluate:
[tex]\bf{\sum^{32}_{n=1}\:(2n+8)[/tex]

Please help A.S.A.P., thank you guys!

Please show work as well.

[tex]\bigstar[/tex]

Sagot :

fieryanswererft

S₃₂ = 1312

Explanation:

[tex]\boxed{\sf \sum _{n=1}^{32}\left(2n+8\right)}[/tex]

Formula Required:

[tex]\sf sum \ of \ arithmetic \ series = \dfrac{n}{2} (2a \ + \ (n-1) \ d)[/tex]

Identify the following's:

  • First Term (a) = (2(1) + 8) = 10

  • Common Difference (d) = 2nd term - first term = (2(2) + 8) - (2(1) + 8) = 2

  • Total Terms (n) = 32

Insert variables:

[tex]\rightarrow \ \sf S_{32} = \dfrac{32}{2} (2(10) + (32-1) 2) \quad \xrightarrow{\text{Simplify} } \quad 1312[/tex]

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.