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An object whose mass is 0.092 kg is initially at rest and then attains a speed of 75.0 m/s in 0.028 s. What average net force acted on the object during this time interval?

Sagot :

Answer:

F = 246.4 N

Explanation:

Concepts:

Newton's Laws Of Motion

First Law: (Law of Inertia)

  • Inertia refers to the tendency of an object to resist any change in its state of motion. Inertia is a measure of the objects mass.

Second Law:

  • refers to an object's motion when a net force does not equal zero. Acceleration is directly proportional to the net force and inversely proportional to the object's mass.

Third Law: (Action - Reaction)

  • Whenever one object exerts a force on a second object, the second objects exert an equal but opposite force on the first.

Weight:

  • Force of gravity is the weight of an object and is measured in Newtons.

Friction:

  • Frictional forces always oppose motion. The frictional forces ([tex]F_f[/tex]) is proportional to the coefficient of friction (Ц) and to the normal force [tex](F_n) F_f=uF_n[/tex].
  • The normal force is a contact force which acts perpendicular to the common surface of contact.

Now onto the steps:
----------------------------------

F = mΔV ÷ t

F = 0.093 x 75 ÷ 0.028

F = 246.4 N

Therefore, the average net force acted on the object during this time interval is 246.6 Newtons.