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A body of mass 250g is release from the top of a building. if the body hits the ground with a velocity of 4m/s, calculate th height of the building [g=10m/s²]​

Sagot :

TwinklingStar

[tex]\purple{\maltese}\large\underline{\underline{\sf\:\: Given :}} \\ [/tex]

» Mass ( m ) of the body = 250 g

» final velocity of the body = 4 m/s

[tex]\\\purple{\maltese}\large\underline{\underline{\sf\:\: To \: \: Find :}} \\ [/tex]

» The height of the Building= ??

[tex]\\\purple{\maltese}\large\underline{\underline{\sf\:\: Solution :}} \\ \\[/tex]

★ Height of the building by the principal of conservation;

[tex]\\\\\begin{gathered}\purple{\maltese}\large\underline{\underline{\sf\:\: using \: formula :}} \\ \\\end{gathered}[/tex]

[tex] \bigstar \: \underline{ \boxed{\sf { \pink{ \: \frac{1}{2} \: \: mv { }^{2} = \: mgh \: }}}} [/tex]

[tex]\\ \: \: \underline{\textsf {Putting values \: in \: the \: \: given \: formula :}} \\ [/tex]

[tex] \\ \sf \implies \: \frac{1}{2} \: \: mv { }^{2} = \: mgh \: \\ [/tex]

[tex] \\ \sf \implies \: \frac{v {}^{2} }{2} \: \: = \: gh \: \\ [/tex]

[tex] \\ \sf \implies \: h \: = \frac{v {}^{2} }{2g} \: \: \: \\ [/tex]

[tex] \\ \sf \implies \: h \: = \frac{16 }{20} \: \: \: \\ [/tex]

[tex] \\ \sf \implies \: h \: = 0.8 \: \: \: m \\ [/tex]

[tex] \\ \sf \implies \: h \: = 80 \: \: \: cm \\ [/tex]

henceforth , The height of the Building is 0.8 m or 80 cm ..!!!

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