praisemickey06
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Someone pls help me ASAP! Express the following as the sum of its partial fraction: 2x+4/x(x+2)(x-4)​

Sagot :

Answer:

Step-by-step explanation:

[tex]\frac{2x+4}{x(x+2)(x-4)} =\frac{a}{x} +\frac{b}{x+2} +\frac{c}{x-4} \\2x+4=a(x+2)(x-4) +bx(x-4)+cx(x+2)\\[/tex]

put x=0

0+4=a(0+2)(0-4)+0+0

-8a=4

a=-4/8=-1/2

put x+2=0 or x=-2

2(-2)+4=0+b(-2)(-2-4)+0

12b=0

b=0

put x-4=0 or x=4

2(4)+4=0+0+c(4)(4+2)

24c=12

c=12/24=1/2

[tex]\frac{2x+4}{x(x+2)(x-4)} =\frac{-1}{2x} +0+\frac{1}{2(x-4)} \\\frac{2x+4}{x(x+2)(x-4)} =\frac{-1}{2x} +\frac{1}{2(x-4)}[/tex]

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