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Solve the following radical equation.
√2x-3 =2

Sagot :

karlaasomohano

Answer:

First, we have to add 3 to both sides.
[tex]\sqrt{2x} - 3 + 3 = 2 + 3[/tex]

Then we simplify the equation,
[tex]\sqrt{2x} = 5[/tex]

Divide both sides of the equation by [tex]\sqrt{2}[/tex]
[tex]\frac{\sqrt{2x} }{\sqrt{2}} = \frac{5}{\sqrt{2}}[/tex]

Finally, simplify.
[tex]x = \frac{5\sqrt{2}}{2}[/tex]

Therefore, our answer is [tex]x = \frac{5\sqrt{2}}{2}[/tex]

alemteihay

3.5

Step-by-step explanation:

square means 1/2.so,1/2(2x-3)=(2)^2

then square cancel by square. 2x-3=4

2x=4+3, 2x=7then divided by 2.

x=3,5

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