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Sagot :
Given data in the problem :-
- Acceleration (a) = 4.0 m/s^2
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 34 m/s
- Distance travelled by aircraft (S) = ?
From Newton's Laws of Motion we know that ,
v = u + at [t = Time taken by aircraft to cover the distance]
⇒ 34 = 0 + 4t
⇒ t = 34/4 s
∴ t = 8.5 s
From Newton's Laws of Motion we also know that ,
S = u.t + 1/2a.t^2
⇒ S = 0×8.5 + 1/2 × 4 × (8.5)^2 m
∴ S = 144.50 m
Thus the distance travelled by the aircraft while accelerating is 144.50 meter .
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