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A small aircraft accelerated down a runway at 4.0 m/s²

The aircraft started from rest and reached a speed of 34 m/s just before take-off.
Calculate the distance the aircraft travelled while accelerating.
Give your answer to 2 significant figures.

Sagot :

Given data in the problem :-

  • Acceleration (a) = 4.0 m/s^2
  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 34 m/s
  • Distance travelled by aircraft (S) =  ?

From Newton's Laws of Motion we know that ,

v = u + at  [t = Time taken by aircraft to cover the distance]

⇒ 34 = 0 + 4t

⇒ t = 34/4 s

∴  t = 8.5 s

From Newton's Laws of Motion we also know that ,

S = u.t + 1/2a.t^2

⇒ S = 0×8.5 + 1/2 × 4 × (8.5)^2 m

∴  S = 144.50 m

Thus the distance travelled by the aircraft while accelerating is 144.50 meter .

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