Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Please solve with explanation (high points)

Please Solve With Explanation High Points class=

Sagot :

konrad509

So, we know that:

[tex]A=\dfrac{1}{2}ab\\P=a+b+c\\a^2+b^2=c^2[/tex]

We also know that [tex](a+b)^2=a^2+2ab+b^2[/tex]. We will use that fact to find [tex]c[/tex] in terms of [tex]A[/tex] and [tex]P[/tex].

[tex]A=\dfrac{1}{2}ab\Rightarrow 2ab=4A\\P=a+b+c\Rightarrow a+b=P-c[/tex]

Therefore:

[tex](P-c)^2=c^2+4A\\P^2-2cP+c^2=c^2+4a\\2cP=P^2-4A\\c=\dfrac{P^2-4A}{2P}[/tex]

View image konrad509
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.