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By applying the equation of dilation, the coordinates of the vertices of the triangle ABC are A'(x, y) = (-12, 0), B'(x, y) = (0, -9) and C'(x, y) = (-12, -9).

How to find the image of a triangle

A dilation is a type of rigid transformation. Rigid transformations are transformations applied to geometric loci such that Euclidean distances are conserved.

There is a triangle and its image must be a triangle, the new triangle is found by transforming the three vertices of the prior one following this formula:

A'(x, y) = P(x, y) + k · [A(x, y) - P(x, y)]     (1)

Where:

  • P(x, y) - Center of reflection.
  • A(x, y) - Original vertex
  • A'(x, y) - New vertex
  • k - Dilation factor

If we know that P(x, y) = (0, 0), A(x, y) = (-4, 0), B(x, y) = (0, -3) and C(x, y) = (-4, -3), then the new vertices of the triangle are, respectively:

Point A

A'(x, y) = (0, 0) + 3 · [(-4, 0) - (0, 0)]

A'(x, y) = (-12, 0)

Point B

B'(x, y) = (0, 0) + 3 · [(0, -3) - (0, 0)]

B'(x, y) = (0, -9)

Point C

C'(x, y) = (0, 0) + 3 · [(-4, -3) - (0, 0)]

C'(x, y) = (-12, -9)

Lastly, we draw the two triangles, which are presented in the image attached below.

To learn more on dilations: https://brainly.com/question/13176891

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