The parallelogram ABCD formed by vertices A(x, y) = (0, 0), B(x, y) = (3, 6) and C(x, y) = (11, 2) has a point D with the following coordinates: D(x, y) = (14, 8).
How to determine the missing vertex of a parallelogram
In this question we know only three vertices of the parallelogram. To determine the missing point we must understand the properties of parallelograms. Vectorially speaking, we can find the missing vertex by using the following property:
[tex]\overrightarrow{AB} = \overrightarrow {CD}[/tex]
[tex]\vec B - \vec A = \vec D - \vec C[/tex]
[tex]\vec D = \vec C + (\vec B - \vec A)[/tex]
D(x, y) = (11, 2) + [(3, 6) - (0, 0)]
D(x, y) = (11, 2) + (3, 6)
D(x, y) = (14, 8)
The parallelogram ABCD formed by vertices A(x, y) = (0, 0), B(x, y) = (3, 6) and C(x, y) = (11, 2) has a point D with the following coordinates: D(x, y) = (14, 8).
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