amy7824
Answered

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The points (4,2) and (-1, y) are √√74 units apart. What is the
value of y?


Please help!!!

The Points 42 And 1 Y Are 74 Units Apart What Is The Value Of Y Please Help class=

Sagot :

Answer:

y = - 5 or y = 9

Step-by-step explanation:

using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = (4, 2 ) and (x₂, y₂ ) = (- 1, y )

d = [tex]\sqrt{(-1-4)^2+(y-2)^2}[/tex]

   = [tex]\sqrt{(-5)^2+(y-2)^2}[/tex]

   = [tex]\sqrt{25+(y-2)^2}[/tex]

equating to [tex]\sqrt{74}[/tex] , that is

[tex]\sqrt{25+(y-2)^2}[/tex]  = [tex]\sqrt{74}[/tex] ( square both sides )

25 + (y - 2)² = 74 ( subtract 25 from both sides )

(y - 2)² = 49 ( take square root of both sides )

y - 2 = ± [tex]\sqrt{49}[/tex] = ± 7 ( add 2 to both sides )

y = 2 ± 7

Then

y = 2 + 7 = 9 or y = 2 - 7 = - 5

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