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an elevator descends into a mine shaft at the rate of 6 m/min. if the descent starts from 10m above the ground level, how long will it take to reach -350m.

Sagot :

Distance descended is denoted by a negative integer,

Initial height =+10 m

Final Depth =−350 m

Total distance to be descended by the elevator =(−350)−(+10)=−360 m

Given, the time is taken by the elevator to descend −6 m=1 minute

Thus, time taken by the elevator to descend −360 m=
(−6)
(−360)
​
------- [from the formula : speed=
time
distance
​
]

Answer =60 minutes
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