Answered

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Solve the following equations for 0 ≤ theta ≤ 360º cosec(2 — 45°) = 2​

Sagot :

sudiptharu2063

Step-by-step explanation:

here ,

[tex]cosec \alpha = \frac{1}{ \sin( \alpha ) } [/tex]

now,

cosec(2-45°)=2

or,

1/sin(2-45°) =2

or,

1/sin2cos45°-cos2sin45=2

or,

[tex] \frac{1}{ \sin(2) \frac{1}{2} - \cos(2) \frac{1}{2} } = 2[/tex]

or,

sorry I have that much qualifications to work on this question and hoping this much will make bit easy for you to solve it further

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