Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

People from two houses 9,000 feet apart are looking up at a plane that is BETWEEN them. House 1 is west of the plane has an angle of elevation of 17.5 degrees and house 2 is east of the plane and has an angle of elevation that is 18.8 degrees. How far is the plane from House 1?

Sagot :

MrRoyal

The distance between the plane and house 1 is 4899.2 feet

How to determine the distance between the plane and house 1?

See attachment for illustration of the question, where x represents the distance between the plane and house 1

Start by calculating the angle A using:

A = 180 - 17.5 - 18.8 ----- (angles in a triangle theorem)

This gives

A = 143.7

The distance x is then calculated using the following sine theorem

a/sin(A) = b/sin(B) = c/sin(C)

Using the parameters in the diagram, we have:

x/sin(18.8) = 9000/sin(143.7)

Multiply both sides by sin(18.8)

x= sin(18.8) * 9000/sin(143.7)

Evaluate

x = 4899.2

Hence, the distance between the plane and house 1 is 4899.2 feet

Read more about angle of elevation at:

https://brainly.com/question/88158

#SPJ1

View image MrRoyal
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.