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Sagot :
let's say the segment is A(-3,8) and B(6,-4) and point C splits it on a 1:5 ratio from A to B, let's check for C coordinates.
[tex]\textit{internal division of a line segment using ratios} \\\\\\ A(-3,8)\qquad B(6,-4)\qquad \qquad \stackrel{\textit{ratio from A to B}}{1:5} \\\\\\ \cfrac{A\underline{C}}{\underline{C} B} = \cfrac{1}{5}\implies \cfrac{A}{B} = \cfrac{1}{5}\implies 5A=1B\implies 5(-3,8)=1(6,-4)[/tex]
[tex](\stackrel{x}{-15}~~,~~ \stackrel{y}{40})=(\stackrel{x}{6}~~,~~ \stackrel{y}{-4})\implies C=\underset{\textit{sum of the ratios}}{\left( \cfrac{\stackrel{\textit{sum of x's}}{-15 +6}}{1+5}~~,~~\cfrac{\stackrel{\textit{sum of y's}}{40 -4}}{1+5} \right)} \\\\\\ C=\left(\cfrac{-9}{6}~~,~~ \cfrac{36}{6} \right)\implies C=\left( -\cfrac{3}{2}~~,~~6 \right)[/tex]
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