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1
F is a force of 3N pulling an object due north and F is a force of 5N pulling an object 60 east of north.
Determine the direction (measured clockwise from north) and magnitude of the resultant force.
2


Sagot :

The direction of the force is given as = 38.21⁰ while the magnitude is given as 7N

The magnitude of the resultant force is given as

Fr = [tex]\sqrt{F1^2+F2^2+2F1F2CosO}[/tex]

∅ = 60 degrees

= √3² + 5² + 2*3*5cos60

= √49

FR = 7N

How to solve for the direction of the force

7cos∅ = 3 + 5cos∅

7cos ∅ = 3 + 2.5

cos∅ = 5.5/7

∅ = cos⁻¹0.7857

= 38.21⁰

Hence the direction of the force is = 38.21⁰

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