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Three numbers have the sum of 112. The first number is twice the second and the third number us twice the first. What is the smallest of the 3 numbers?

Sagot :

Answer:

x = 16

Step-by-step explanation:

Let the second number be x.

The first number = 2x

The third number = 2×2x = 4x

2x + x + 4x = 112

7x = 112

x = 112/7

x = 16

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