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What is the pH of a solution that contains 0.0003 moles of KOH in 410 mL of solution?

Sagot :

Medunno13

Answer: 10.865

Explanation:

The molarity of the solution is [tex]\frac{0.0003}{0.410}=0.0007317073 \text{ M}[/tex].

So, the pOH is [tex]-\log(0.0007317073)=3.135[/tex]

Since pH + pOH = 14, the pH is 14-3.135, which is about 10.865

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