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Bo is flying a kite, holding his hands a distance of 3.5 feet above the ground and
letting all the kite's string play out. He measures the angle of elevation from his hand
to the kite to be 29°. If the string from the kite to his hand is 110 feet long, how many
feet is the kite above the ground? Round your answer to the nearest tenth of a foot if
necessary.

Sagot :

shubhamchouhanvrVT

The height of the kite will be 53.32 feet above the ground.

What is trigonometry?

The branch of mathematics sets up a relationship between the sides and the angles of the right-angle triangle is termed trigonometry.

Given that:-

  • The boy is flying a kite, holding his hands a distance of 3.5 feet above the ground and
  • letting all the kite's strings play out. He measures the angle of elevation from his hand to the kite to be 29°. If the string from the kite to his hand is 110 feet long, what is the total vertical height?

The height of the kite above the ground will be calculated as:-

[tex]Sin\theta = \dfrac{perpendicular}{Hypotenuse}[/tex]

[tex]Sin(29)=\dfrac{H}{110}[/tex]

H = Sin(29)  x  110

H  = 53.32 feet

The hand of the boy is 3.5 above the ground so the total height H(t) of the kite above the ground will be:-

H(t)  = 53.232  +  3.5

H(t)  = 56.28 feet.

Therefore the height of the kite will be 53.32 feet above the ground.

To know more about Trigonometry follow

https://brainly.com/question/24349828

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