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what is the vertex of: y = x^2 + 8x - 10

Sagot :

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Answer:

vertex = -4, -26

Step-by-step explanation:

The standard form of a quadratic function is : [tex]y=ax^{2} +bx+c[/tex]
The function here : y = [tex]x^{2}[/tex] + 8x - 10
is in this form with a=1, b=8 and c = -10
x-coord of vertex = [tex]\frac{-b}{2a}[/tex]
[tex]x_{vertex} =\frac{-8}{2} = -4[/tex]
To find corresponding value of y-coord of vertex , substitute

x = -4 into the function.
x=-4  : [tex]y=(-4)^{2} +(8*(-4))-10 = 16 +(-32)-10=-26[/tex]


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