Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

An object with charge -4.0μC is placed between a positively charged object to the
left and a negatively charged object to the right that exert electric fields with magnitudes of 1.2 N/C and 1.4 N/C respectively.

What is the net force on the -4.0μC object as a result of this net field?


Sagot :

The net force on the -4.0μC object as a result of this net field will be -10.4 N.

What is the charge?

The matter has an electric charge when it is exposed to an electromagnetic field is known as a charge.

The electric field intensity is found as the force per unit charge.

Electric field intensity on the positive charge:

[tex]\rm E_1 = \frac{F_1}{Q} \\\\\ \rm 1.2 N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_1 = - 4.8 \ N[/tex]

Electric field intensity on the negative charge:

[tex]\rm E_2 = \frac{F_2}{Q} \\\\\ \rm 1.4 \ N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_2 = - 5.6 \ N[/tex]

The net charge is the algebraic sum of the two charges;

[tex]\rm F_{net}=F_1+F_2 \\\\ F_{net}= -4.8 -5.6 \\\\ F_{net}=-10.4 \ N[/tex]

Hence, as a result of this net field, the net force on the -4.0C object will be -10.4 N.

To learn more about the charge refer to the link;

https://brainly.com/question/24391667

#SPJ1