Answer:
25 in x 15 in
Step-by-step explanation:
Given:
- Length = 3/5 the width
- Area = 375 in²
Let width = [tex]x[/tex]
Therefore, length = 3/5 [tex]x[/tex]
First create an equation for the area of the picture based on the given information for its width and length:
[tex]\begin{aligned} \implies \textsf{Area of original picture} & = \sf width \times length\\& = x\left(\dfrac{3}{5}x\right)\\& = \dfrac{3}{5}x^2\end{aligned}[/tex]
We are told the area of the enlarged picture is 375 in². Therefore, substitute this into the equation and solve for [tex]x[/tex] to find the width of the enlarged picture:
[tex]\begin{aligned}\textsf{Area} & = 375\\ \implies \dfrac{3}{5}x^2 & = 375\\ x^2 & =375 \cdot \dfrac{5}{3}\\ x^2 & =625\\ x & = \sqrt{625}\\ x& = 25\end{aligned}[/tex]
Therefore, the width of the enlarged picture is 25 in.
Substitute the found value of [tex]x[/tex] into the expression for length to find the length of the enlarged picture:
[tex]\begin{aligned}\sf Length & = \dfrac{3}{5}x\\\\\implies \sf Length & = \dfrac{3}{5}(25)\\\\& = 15\: \sf in\end{aligned}[/tex]
Therefore, the dimensions of the enlarged picture are 25 in x 15 in. The width is 25 in and the length is 15 in, as the length is 3/5 of the width.
