richmondondabu64
Answered

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7. A man leaves ⅓of his property to his son, two fifths to his wife and the remainder to his daughter. If the daughter received sh. 24,000, what was the total amount left?​

Sagot :

Answer:

sh 90,000

Step-by-step explanation:

let x be the total amount left , then

x = [tex]\frac{1}{3}[/tex] x + [tex]\frac{2}{5}[/tex] x + 24,000

multiply through by 15 ( the LCM of 3 and 5 ) to clear the fractions

15x = 5x + 6x + 360,000

15x = 11x + 360,000 ( subtract 11x from both sides )

4x = 360,000 ( divide both sides by 4 )

x = 90,000

the total amount left was sh 90,000

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