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Check whether the following differential equation is exact or not. If not, then convert it into an exact differential equation.

[tex]2ydx+(x-sin\ y^{\frac{1}{2} } )dy =0[/tex]

Sagot :

facundo3141592

The given differential equation is not exact, if we convert it to an exact one, we get:

[tex]2ydx + 2*(x - sin(y)^{1/2})*dy = 0[/tex]

Is the differential equation exact or not?

A differential equation:

[tex]Ndx + Mdy = C[/tex]

Is exact only if:

[tex]\frac{dM}{dy} = \frac{dN}{dx}[/tex]

In this case, we have:

[tex]2ydx + (x - sin(y)^{1/2})*dy = 0\\\\then:\\\\N = 2y\\M = x - sin(y)^{1/2}[/tex]

If we differentiate, we will get:

[tex]\frac{dN}{dy} = 2\\\\\frac{dM}{dx} = 1[/tex]

So, to convert this to an exact differential equation, we need to add a factor 2 to N, this will give:

[tex]2ydx + 2*(x - sin(y)^{1/2})*dy = 0[/tex]

This is, in fact, an exact differential equation.

If you want to learn more about differential equations:

https://brainly.com/question/18760518

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