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match each pair of rational numbers with their sum

Match Each Pair Of Rational Numbers With Their Sum class=

Sagot :

The matched pair of rational numbers are as follows;

[tex]\frac{-2}{a^{2}b }+\frac{2}{ab^{2} } = \frac{2(a-b)}{a^{2}b^{2} }[/tex]

[tex]\frac{1}{2ab} +\frac{-1}{4a^{2} b^{2} } =\frac{2ab-1}{4a^{2}b^{2} }[/tex]

[tex]\frac{2}{a^{2} b^{3} } +\frac{-2}{ab} =\frac{2(1-ab^{2} )}{a^{2} b^{3} }[/tex]

[tex]\frac{1}{ab^{3} } +\frac{-1}{a^{2} b} =\frac{a-b^{2} }{a^{2}b^{3} }[/tex]

How to simplify rational numbers?

The matched pair of rational numbers are as follows:

[tex]\frac{-2}{a^{2}b }+\frac{2}{ab^{2} } = \frac{-2b+2a}{a^{2} b^{2} } = \frac{2(a-b)}{a^{2}b^{2} }[/tex]

[tex]\frac{1}{2ab} +\frac{-1}{4a^{2} b^{2} } =\frac{2ab-1}{4a^{2}b^{2} }[/tex]

[tex]\frac{2}{a^{2} b^{3} } +\frac{-2}{ab} =\frac{2 - 2ab^{2} }{a^{2}b^{3} } =\frac{2(1-ab^{2} )}{a^{2} b^{3} }[/tex]

[tex]\frac{1}{ab^{3} } +\frac{-1}{a^{2} b} =\frac{a-b^{2} }{a^{2}b^{3} }[/tex]

learn more on rational numbers here: brainly.com/question/12512979

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