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Sagot :
Answer:
Solution: Here, the given equations are,
[tex]: \implies8x+5y=2...(i)\:and\:y-2=0...(ii)[/tex]
From equation,(ii); y-2=0
[tex] \therefore \: y = 2.........(iii)[/tex]
Substituting the value of y from equation (iii) to equation (i),we get
[tex]: \implies{8x + 5y = 2}[/tex]
[tex]: \implies{8x + 5(2) = 2}[/tex]
[tex]: \implies{8x = 2 - 10}[/tex]
[tex]: \implies{8x = - 8}[/tex]
[tex]: \implies{x = - 1}[/tex]
[tex] \therefore \: x = - 1[/tex]
Thus, x= -1 and y= 2 is the solution.
- Checking at (-1,2)
8x+5y=2...(i) y-2=0...(ii)
8(-1)+5(2)=2 2-2=0
2=2(True) 0=0(True)
Answer: x = -1, y = 2
Step-by-Step Explanation:
=> 8x + 5y = 2 (Eq. 1)
=> y - 2 = 0 (Eq. 2)
We can Solve Eq. 2 :-
y - 2 = 0
=> y = 2
Substitute value of ‘y’ in Eq. 1 :-
8x + 5y = 2
8x + 5(2) = 2
8x + 10 = 2
8x = 2 - 10
8x = -8
x = -8/8
=> x = -1
Therefore; x = -1, y = 2
Step-by-Step Explanation:
=> 8x + 5y = 2 (Eq. 1)
=> y - 2 = 0 (Eq. 2)
We can Solve Eq. 2 :-
y - 2 = 0
=> y = 2
Substitute value of ‘y’ in Eq. 1 :-
8x + 5y = 2
8x + 5(2) = 2
8x + 10 = 2
8x = 2 - 10
8x = -8
x = -8/8
=> x = -1
Therefore; x = -1, y = 2
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