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Sagot :
The perimeter and area of the equilateral, isosceles and right angled triangle are 16.2mm 12.6mm², 15.2in and 9.61in², 21.47yds and 16.81yds² respectively.
What is the area of the equilateral, isosceles and right angle triangle?
Note that:
The perimeter of an Equilateral triangle is expressed as P = 3a
The area of an Equilateral triangle is expressed as A = ((√3)/4)a²
Where a is the dimension of the side.
The perimeter of an Isosceles triangle is expressed as P = 2a + b
The area of an Isosceles triangle is expressed as A = (ah)/2
Where b is the slant height, a is the dimension of the base and h is the height.
The perimeter of a Right angled triangle is expressed as P = a + b + c
The area of a Right angled triangle is expressed as A = (ab)/2
Where a and b is the dimension of the two sides other than the hypotenuse and c is the hypotenuse.
For the Equilateral triangle.
Given that;
- a = 5.4mm
- Perimeter P = ?
- Area A = ?
Perimeter P = 3a
P = 3 × 5.4mm
P = 16.2mm
Area A = ((√3)/4)(5.4mm)²
A = ((√3)/4)( 29.16mm² )
A = 12.6mm²
The Perimeter and Area of the Equilateral triangle are 16.2mm 12.6mm² respectively.
For the Isosceles triangle.
Given that;
- Base a = 3.4in
- Slant height b = 5.9in
- Perimeter P = ?
- height h = ?
- Area A = ?
Perimeter P = 2a + b
P = 2(b) + a
P = 2(5.9in) + 3.4in
P = 11.8in + 3.4in
P = 15.2in
The height h is the imaginary line drawn upward from the center of a.
First, we calculate the height using Pythagorean theorem
x² = y² + z²
Where x = b = 5.9in, y = a/2 = 3.4in/2 = 1.7in, and z = h
(5.9in)² = (1.7in)² + h²
34.81in² = 2.89in² + h²
h² = 34.81in² - 2.89in²
h² = 31.92in²
h = √31.92in²
h = 5.65in
Now, the area will be;
A = (ah)/2
A = (3.4in × 5.65in )/2
A = 19.21in²/2
A = 9.61in²
The Perimeter and Area of the Isosceles triangle are 15.2in and 9.61in² respectively.
For the Right angled triangle.
Given that;
- a = 8.2yds
- b = 4.1yds
- c = 9.17yds
- Perimeter P = ?
- Area A = ?
Perimeter P = a + b + c
P = 8.2yds + 4.1yds + 9.17yds
P = 21.47yds
Area A = (ab)/2
A = ( 8.2yds × 4.1yds)/2
A = ( 33.62yds²)/2
A = 16.81yds²
The Perimeter and Area of the Right angled triangle are 21.47yds and 16.81yds² respectively.
Therefore, the perimeter and area of the equilateral, isosceles and right angled triangle are 16.2mm 12.6mm², 15.2in and 9.61in², 21.47yds and 16.81yds² respectively.
Learn more about Pythagorean theorem here: brainly.com/question/343682
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