Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
2.59 atm is the pressure inside the flask if 6 grams of nitrogen gas is introduced into an evacuated 2 L flask at 28 degrees celsius.
What is an ideal gas equation?
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
The computation of the pressure inside the flask is shown below;
As per the ideal gas law
we know that
P V = nRT
where
V = 2 L
T = 28 degrees celsius +273 = 301 K
m= 6 grams
R = 0.0821
Now moles of [tex]N_2[/tex] is
= 6 grams ÷ 28
= 0.21 mol
Now
P = nRT ÷ V
= (0.21 mol × 0.0821 × 301 K) ÷ 2 L
= 2.59 atm
Learn more about the ideal gas here:
https://brainly.com/question/27691721
#SPJ1
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
