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if 6 grams of nitrogen gas is introduced into an evacuated 2 L flask at 28 degrees celsius, what is the pressure inside the flask?

Sagot :

2.59 atm is the pressure inside the flask if 6 grams of nitrogen gas is introduced into an evacuated 2 L flask at 28 degrees celsius.

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

The computation of the pressure inside the flask is shown below;

As per the ideal gas law

we know that

P V = nRT

where

V = 2 L

T = 28 degrees celsius +273 = 301 K

m= 6 grams

R = 0.0821

Now moles of [tex]N_2[/tex] is

= 6 grams ÷ 28

= 0.21 mol

Now

P = nRT ÷ V

= (0.21 mol × 0.0821 × 301 K) ÷ 2 L

= 2.59 atm

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