Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A chemist uses 22.0 mL of 0.10 M H₂SO4 to neutralize 10.0 mL of NaOH. What is the concentration of the NaOH solution?
2 A 044M
OB. 0.22 M
O C 0.11 M
OD. 0.055 M

Sagot :

Eduard22sly

The concentration of the NaOH solution required for the reaction given the data is 0.44 M

Balanced equation

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₂SO₄ (nA) = 1
  • The mole ratio of the base, NaOH (nB) = 2

How to determine the concentration of NaOH

  • Volume of acid, H₂SO₄ (Va) = 22 mL
  • Concentration of acid, H₂SO₄ (Ca) = 0.1 M
  • Volume of base, NaOH (Vb) = 10 mL
  • Concentration of base, NaOH (Cb) =?

CaVa / CbVb = nA / nB

(0.1 × 22) / (Cb × 10) = 1 / 2

2.2 / (Cb × 10) = 1 / 2

Cross multiply

Cb × 10 = 2.2 × 2

Cb × 10 = 4.4

Divide both side by 10

Cb = 4.4 / 10

Cb = 0.44 M

Thus, the concentration of the NaOH solution is 0.44 M

Learn more about titration:

https://brainly.com/question/14356286

#SPJ1

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.