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A chemist uses 22.0 mL of 0.10 M H₂SO4 to neutralize 10.0 mL of NaOH. What is the concentration of the NaOH solution?
2 A 044M
OB. 0.22 M
O C 0.11 M
OD. 0.055 M

Sagot :

Eduard22sly

The concentration of the NaOH solution required for the reaction given the data is 0.44 M

Balanced equation

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₂SO₄ (nA) = 1
  • The mole ratio of the base, NaOH (nB) = 2

How to determine the concentration of NaOH

  • Volume of acid, H₂SO₄ (Va) = 22 mL
  • Concentration of acid, H₂SO₄ (Ca) = 0.1 M
  • Volume of base, NaOH (Vb) = 10 mL
  • Concentration of base, NaOH (Cb) =?

CaVa / CbVb = nA / nB

(0.1 × 22) / (Cb × 10) = 1 / 2

2.2 / (Cb × 10) = 1 / 2

Cross multiply

Cb × 10 = 2.2 × 2

Cb × 10 = 4.4

Divide both side by 10

Cb = 4.4 / 10

Cb = 0.44 M

Thus, the concentration of the NaOH solution is 0.44 M

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