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Write the equation of a line in slope-intercept form, that passes through the point (6,-4) and its parallel to the line y=3x-8

y=

Sagot :

rspill6

Answer:

Step-by-step explanation:

We'll look for a line with the form of y = mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).

A parallel line will have the same slope as the reference line,  For y=3x-8, the slope is 3.  We can write:

y =3x + b for the new line.  We need a value of b that will cause the line to include point (6,-4).  To find a b that will work, simple use the given point in the above equation and solve for b:

y =3x + b

-4 =3(6) + b  for (6,-4)

-4 =18 + b

b = -22

The parallel line that goes through point (6,-4) is y = 3x - 22

See the attached graph.

View image rspill6
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