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A bicyclist moving at a constant speed takes 10.0 seconds to travel 500 meters down a path inclined 30.0° downward from the horizontal. what is the vertical velocity of this motion? a. 18.3 meters/second b. 43.3 meters/second c. 25.0 meters/second d. 28.9 meters/second e. 32.1 meters/second

Sagot :

A bicyclist moving at a constant speed takes 10.0 seconds to travel 500 meters down a path inclined 30.0° downward from the horizontal. the vertical velocity of this motion is mathematically given as

V' = 25 m/s. Option C.

What is the vertical velocity of this motion?

Generally, the equation for the Inclined Component is mathematically given as

V=d/s

Therefore

V = 500/10

V= 50 m/s

In conclusion, for the vertical Component

[tex]V'= dsin \theta[/tex]

V'= 50Sin30

V' = 25 m/s

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