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Sagot :
The confidence Interval is CI = (-1.35, 1.35) and 1.74 is outside of this confidence interval and as such it is statistically significant.
How to find the confidence Interval?
Formula for the confidence interval is:
CI = x' ± z(S.E)
where;
x is the mean
z is the critical value.
S.E is the standard error.
We are told that there is no difference between the population and as such; x = 0.
The confidence level is given as 95%.
z-score at 95% confidence level = 1.96.
Standard deviation of the sample mean differences is 0.69. Thus;
S.E = 0.69.
The confidence interval is:
CI = 0 ± (1.96 * 0.69)
CI = (-1.35, 1.35)
1.74 is outside of this confidence interval and as such it is statistically significant.
Complete question is;
I know that the red box has a mean value of 15.11 and the blue box's mean is 16.83. The difference of sample means is 1.74. The red standard deviation is 3.868 and the blue one is 2.933. the standard deviation of the sample mean differences is 0.69. How do I use all this to construct the interval with no difference between the population means.
Read more about Confidence Interval at; https://brainly.com/question/17097944
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