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What is the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b?
1.
8.42 ev
2.
5.74 ev
3
3.06 ev
4.
2.68 ev

Sagot :

onyebuchinnaji

The energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

Change in energy level of the electron

When photons jump from a higher energy level to a lower level, they emit or radiate energy.

The change in energy level of the electrons is calculated as follows;

ΔE = Eb - Ef

ΔE = -2.68 eV - (-5.74 eV)

ΔE = 3.06 eV

Thus, the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

Learn more about energy level here: https://brainly.com/question/14287666

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