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Sagot :
We will see that, when evaluated in x = 0, g(x) is larger than f(x).
How to compare the functions when x = 0?
First, we can see that:
g(x) = x + 3
Then, evaluating it in x = 0 we get:
g(0) = 0 + 3 = 3
Now, if we go to the table that represents f(x), we can see that it has the point (0, -6).
Then we can get:
f(0) = -6
With that, we can conclude that: g(0) > f(0), so the correct option is the first one.
If you want to learn more about evaluating functions:
https://brainly.com/question/1719822
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