Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
We will see that, when evaluated in x = 0, g(x) is larger than f(x).
How to compare the functions when x = 0?
First, we can see that:
g(x) = x + 3
Then, evaluating it in x = 0 we get:
g(0) = 0 + 3 = 3
Now, if we go to the table that represents f(x), we can see that it has the point (0, -6).
Then we can get:
f(0) = -6
With that, we can conclude that: g(0) > f(0), so the correct option is the first one.
If you want to learn more about evaluating functions:
https://brainly.com/question/1719822
#SPJ1
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.