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4 there are only red sweets and yellow sweets in a bag.
there are n red sweets in the bag.
there are 8 yellow sweets in the bag.
sajid is going to take at random a sweet from the bag and eat it.
7
he says that the probability that the sweet will be red is
10
7
(a) show why the probability cannot be
10
after sajid has taken the first sweet from the bag and eaten it, he is going to take at
random a second sweet from the bag.
given that the probability that both the sweets he takes will be red is
uw
(b) work out the number of red sweets in the bag.
you must show all your working.

Sagot :

shubhamchouhanvrVT

Using the probability concept, it is found that since the number of red sweets would be a decimal number, the probability cannot be [tex]\dfrac{7}{10}[/tex]

What is probability?

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

In this problem:

  • In total, there are 8 + n sweets in the bag.
  • Of those, n are red.

The probability of red is:

[tex]p=\dfrac{n}{n+8}[/tex]

Supposing, we solve for n:

[tex]\dfrac{n}{n+8} = \dfrac{7}{10}[/tex]

10n = 7n + 56

3n = 56

n  =  56 / 3

n  =  18.67

Since the number of red sweets would be a decimal number, the probability cannot be 7 / 10

To know more about probability follow

https://brainly.com/question/24756209

#SPJ1

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