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Sagot :
The total electric field of the rod at a distance, x to the right hand end of the rod is determined as [tex]E = \frac{\lambda}{4\pi \varepsilon _0} [\frac{1}{x} - \frac{1}{x+ l} ][/tex].
Expression for the electric field
An expression for the electric field due to an arbitrary source location at observation location on the x-axis is determined as follows;
E = kq/r²
where;
- k is coulomb's constant
- r is the distance on x - axis
Total electric field of the entire rod
[tex]\int\limits {dE} \,=\int\limits {\frac{kdQ}{r^2} }\\\\E = \lambda k \int\limits^{x + l}_x {\frac{dr}{r^2}} \,= \lambda k [-\frac{1}{r} ] \\\\E = \lambda k [\frac{1}{x} - \frac{1}{x+ l} ]\\\\E = \frac{\lambda}{4\pi \varepsilon _0} [\frac{1}{x} - \frac{1}{x+ l} ][/tex]
Thus, the total electric field of the rod at a distance, x to the right hand end of the rod is determined as [tex]E = \frac{\lambda}{4\pi \varepsilon _0} [\frac{1}{x} - \frac{1}{x+ l} ][/tex].
Learn more about electric field here: https://brainly.com/question/14372859
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