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For the reaction:
H₂O(1)→ H₂O(g)
ΔΗ = 44 kJ
How much heat is required when 9.0 g of H₂O is used?


Sagot :

1mol H_2O requires 44kJ heat

Moles of water

  • Given mass/Molar mass
  • 9/18
  • 1/2
  • 0.5mol

Heat required

  • 0.5(44)
  • 22kJ

As per the reaction given

Moles of H_2O=1

  • ∆H=44kJ

Moles of water in 9g

  • Given mass/Molar mass
  • 9g/18g/mol
  • 0.5mol

∆H

  • 44(0.5)
  • 22KJ