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Graph (x-2)^2 + (y-1)^2 = 9

Graph X22 Y12 9 class=

Sagot :

Nonportrit

Step-by-step explanation:

Given the following question:

[tex](x-2)^2+(y-2)^2=9[/tex]

First thing we need to keep in mind is the fact that this graph is indeed a circle. We know this because we are adding two cubic roots to each other which makes the graph a circle. We know the two separate functions are cubic roots because they each have an exponent of two. Not only is this function whose graph is a circle, but the midpoint of this circle is (2,2).

Hope this helps.

View image Nonportrit
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