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g(x) = x3 + 6x2 + 12x + 8

A 2-column table with 5 rows. The first column is labeled g of x with entries negative 3, negative 2, 0, 2, 3. The second column is labeled f of x with entries negative 1, 0, 8, 64, 125.

Determine the function’s value when x = −1.

Sagot :

MrRoyal

The value of the function g(x) = x^3 + 6x^2 + 12x + 8 when x = -1 is 1

How to evaluate the function?

The equation of the function is given as:

g(x) = x^3 + 6x^2 + 12x + 8

When x = -1, we have:

g(-1) = (-1)^3 + 6(-1)^2 + 12(-1) + 8

Evaluate the expression

g(-1) = 1

Hence, the value of the function g(x) = x^3 + 6x^2 + 12x + 8 when x = -1 is 1

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severalsafe

Answer:

g(-1) = 1

Step-by-step explanation:

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